4.9x^2=22x

Solution for 4.9x^2=22x equation:

4.9x^2=22x

We move all terms to the left:

4.9x^2-(22x)=0

a = 4.9; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·4.9·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*4.9}=\frac{0}{9.8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*4.9}=\frac{44}{9.8}
=4+2.66666666667/5.44444444444
$